The Solution
Solving the model, we get the following nonzero values for TD:
Variable Value
TD( U, 7) 10.00000
TD( B, 7) 20.00000
TD( T, 8) 20.00000
TD( S, 6) 30.00000
TD( S, 7) 40.00000
TD( W, 4) 50.00000
TD( W, 5) 40.00000
TD( C, 6) 20.00000
TD( C, 7) 40.00000
TD( H, 3) 50.00000
TD( H, 4) 40.00000
TD( P, 2) 1800.000
TD( P, 3) 1440.000
TD( L, 4) 1680.000
TD( L, 5) 3360.000
Solution: MRP
Putting this solution in tabular form, we get the following production schedule:
MRP Production Schedule:
|
2 |
3 |
4 |
5 |
6 |
7 |
8 |
Unicycles |
|
|
|
|
|
10 |
|
Bicycles |
|
|
|
|
|
20 |
|
Tandems |
|
|
|
|
|
|
20 |
Seats |
|
|
|
|
30 |
40 |
|
Wheels |
|
|
50 |
40 |
|
|
|
Chains |
|
|
|
|
20 |
40 |
|
Hubs |
|
50 |
40 |
|
|
|
|
Spokes |
1,800 |
1,440 |
|
|
|
|
|
Links |
|
|
1,680 |
3,360 |
|
|
|
Note the use of the @TABLE output function in the data section at the end of the model that displays the TD attribute in table form similar to the table above:
The production schedule:
1 2 3 4 5 6 7 8 9
U 0 0 0 0 0 0 10 0 0
B 0 0 0 0 0 0 20 0 0
T 0 0 0 0 0 0 0 20 0
S 0 0 0 0 0 30 40 0 0
W 0 0 0 50 40 0 0 0 0
C 0 0 0 0 0 20 40 0 0
H 0 0 50 40 0 0 0 0 0
P 0 1800 1440 0 0 0 0 0 0
L 0 0 0 1680 3360 0 0 0 0